Respuesta :
Answer:
1000.66m
Explanation:
[tex]l 2 = l1(1 + \alpha \: \times change \:in \: temperature)[/tex]
L1=1000m
Temperature 1=-20
L2=?
Temperature 2=40
Temperature difference=40-(-20)
40+20=60
inserting into the formula
l2=l1(1+α×changeintemperature)
L2=1000(1+11×10^-6 ×60)
L2=1000(1+6.6×10^-4)
L2=1000(1.000.66)
L2=1000.66m
Answer :-
l2 = l1 (1 + α × change in temperature)
L1 = 1000m
Temperature 1 = -20
L2 = ?
Temperature 2 = 40
Temperature difference = 40 - (- 20)
40+20=60
Inserting into the formula
- l2 = l1 (1 + α × change in temperature)
- L² = 1000(1+11×10^-6 ×60)
- L² = 1000(1+6.6×10^-4)
- L² = 1000(1.000.66)
- L² = 1000.66m Ans.