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How much charge is needed to repel another charge of 9.9 x 10^-6 N when they are 200m apart? Please help meee I really can't understand Coulomb's Law : (

Respuesta :

Answer:

The charge needed will be [tex]q=6.6\: \mu C[/tex]

Step-by-step explanation:

The equation of the electric force is given by:

[tex]F=k\frac{qQ}{r^{2}}[/tex]

We have the force [tex]F = 9.9 10^{-6}\: N[/tex]  and the distance r = 200. k is the Coulomb constant. Q and q are the charges.

We assume we have the same charge of the particles,  so we have:

[tex]q^{2}=\frac{Fr^{2}}{k}[/tex]

[tex]q^{2}=\frac{9.9*10^{-6}200^{2}}{9*10^{9}}[/tex]

[tex]q=6.6*10^{-6}\: C[/tex]

Therefore, the charge needed will be [tex]q=6.6\: \mu C[/tex]

I hope it helps you!