Answer:
67.28 N
Explanation:
Given that,
The mass of an box, m = 15.2 kg
The coefficients of static and kinetic frictions for plastic on wood are 0.55 and 0.36, respectively.
The force of static friction,
[tex]F_s=\mu_smg\\\\F_s=0.55\times 15.2\times 9.8\\\\F_s=81.92\ N[/tex]
The force of kinetic friction,
[tex]F_k=\mu_kmg\\\\F_k=0.36\times 15.2\times 9.8\\\\F_k=53.62\ N[/tex]
Net force acting on the object is :
F = 120.9 -53.62
= 67.28 N
Hence, this is the required solution.
