Respuesta :

arslanamir186

Answer:

25.30 gram

Explanation:

No of moles = given mass / molar mass

No of moles = 63.17/80.06

0.7890 moles

Mass of sulphar = no of moles× molar mass of sulphar

Mass of sulphur = 0.7890×32.065

25.30 gram

Oseni

The amount of sulfur in 63.17 g sample of SO3 would be 25.25 g

Moles

The mole of any substance is given by: mass/molar mass

mole of 63.17 g SO3 = 63.17/80.06

                                  = 0.79 moles

Stoichiometrically:  SO3 ---> S + 3O

Mole ratio of SO3 to S = 1:1

Thus, equivalent mole of S = 0.79 moles

Mass of 0.79 moles S = 0.79 x 32

                                     = 25.25 g

More on mole ratios can be found here: https://brainly.com/question/15288923?referrer=searchResults

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