Answer:
The object hits the ground after 3.52 seconds.
Step-by-step explanation:
The height of the object after t seconds is given by the following function:
[tex]h(t) = -16t^2 + 198[/tex]
When will the object hit the ground?
It hits the ground when [tex]h(t) = 0[/tex]. So
[tex]-16t^2 + 198 = 0[/tex]
[tex]16t^2 = 198[/tex]
[tex]t^2 = \frac{198}{16}[/tex]
[tex]t^2 = 12.375[/tex]
[tex]t = \pm \sqrt{12.375}[/tex]
Since time is a positive measure, we only take the positive value
[tex]t = 3.52[/tex]
The object hits the ground after 3.52 seconds.
