9514 1404 393
Answer:
2/3·fg
Step-by-step explanation:
The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
(a^b)/(a^c) = a^(b-c)
(ab)^c = (a^c)(b^c)
(a^b)^c) = a^(bc)
__
We assume your 'x' is a multiplication symbol, so you want to simplify ...
[tex]3f^4g^3 \times\dfrac{ 8fg^4}{ (6f^2g^3)^2}\\\\=\dfrac{3\cdot8f^{4+1}g^{3+4}}{6^2f^{2\cdot2}g^{3\cdot2}}=\dfrac{24}{36}f^{5-4}g^{7-6}\\\\=\boxed{\dfrac{2}{3}fg}[/tex]
