Respuesta :

elizabetheghosa195

Answer:

N(CO2) = n(CO2) x Avogadros constant

n(CO2) = mass(CO2)/Molar mass(CO2) = 112/44 = 2.5454….

N(CO2) = 2.545454… x (6.02 x 10^23) = 1.5323636 x 10^24

Therefore, the number of CO2 molecules in 112 g of CO2 = 1.53 x 10^24 molecules

Space

Answer:

1.53 × 10²⁴ molecules CO₂

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Reading a Periodic Table
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

  • Using Dimensional Analysis

Explanation:

Step 1: Define

112 g CO₂

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of C - 12.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

Step 3: Convert

  1. [Dimensional Analysis] Set up:                                                                      [tex]\displaystyle 112 \ g \ CO_2(\frac{1 \ mol \ CO_2}{44.01 \ g \ CO_2})(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2})[/tex]
  2. [Dimensional Analysis] Multiply/Divide [Cancel out units]:                          [tex]\displaystyle 1.53252 \cdot 10^{24} \ molecules \ CO_2[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.53252 × 10²⁴ molecules CO₂ ≈ 1.53 × 10²⁴ molecules CO₂

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