Answer:
a) x =18
b) x=2
c) x=3
Step-by-step explanation:
Step(i):-
a)
Given that [tex](x-2)^{\frac{1}{4} }[/tex]
put x = 18
⇒ [tex](18-2)^{\frac{1}{4} } = (2^{4} )^{\frac{1}{4} } = 2[/tex]
[tex](x-2)^{\frac{1}{4} }[/tex] =2
b)
put x= 2
[tex](1-x)^{\frac{1}{3} } = (1-2)^{\frac{1}{3} } = (-1)^{\frac{1}{3} } = -1[/tex]
[tex](1-x)^{\frac{1}{3} } = -1[/tex]
c)
put x=3
[tex]\sqrt{x^{2} +7} = \sqrt{3^{2} +7} = \sqrt{16} = 4[/tex]
[tex]\sqrt{x^{2} +7}= 4[/tex]
