[tex] \sf{(i) \: We \: are \: given \: a \: figure \: of \: Series \: Circuit. }[/tex]
[tex] \sf{Here \: Resistances \: are ,}[/tex]
[tex] \sf• \: R_{1} =3 Ω[/tex]
[tex] \sf• \: R_{2} =3Ω[/tex]
[tex] \sf• \: R_{3} =3Ω[/tex]
[tex] \sf{We \: know \: the \: formula \: of \: the \: Equivalent \: Resistance \: for \: Series \: Circuit, }[/tex]
[tex] \bf \purple {\bigstar {\: R_{s} = R _{1} + R _{2} + R_{3}+...+ R_{n}}}[/tex]
[tex] \sf ⇒ R_{s} =(3 + 3 + 3)Ω[/tex]
[tex] \sf \therefore R_{s} =9Ω[/tex]
[tex] \sf \pink{ \boxed{Answer : 9 Ω.}}[/tex]
[tex] \\ \\ [/tex]
[tex] \sf{(ii) \: We \: are \: given \: a \: figure \: of \: Parallel \: Circuit. }[/tex]
[tex]\sf{Here \: Resistances \: are ,}[/tex]
[tex] \sf• \: R_{1} =3 Ω[/tex]
[tex] \sf• \: R_{2} =3 Ω[/tex]
[tex] \sf• \: R_{3} =3 Ω[/tex]
[tex] \sf{We \: know \: the \: formula \: of \: the \: Equivalent \: Resistance \: for \: Parallel \: Circuit, }[/tex]
[tex] \bf \purple {\bigstar {\: \frac{1}{R_{p}} = \frac{1}{R _{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}}+...+\frac{1}{R_{n}} }}[/tex]
[tex] \sf⇒ \frac{1}{ R_{p} } = \frac{1}{3} + \frac{1}{3} + \frac{1}{3} [/tex]
[tex] \sf⇒ \frac{1}{ R_{p} } = \frac{1 + 1 + 1}{3} [/tex]
[tex] \sf⇒ \frac{1}{ R_{p} } = \frac{3}{3} [/tex]
[tex] \sf⇒ \frac{1}{ R_{p} } = 1[/tex]
[tex] \sf \therefore R_{p} = 1Ω[/tex]
[tex] \sf \pink{ \boxed{Answer : 1 Ω.}}[/tex]
