contestada

The second hand on Mr. Vidler's Alarm Clock is 6 cm long. Approximately how far does the tip travel in 5 minutes and 15 seconds? [Round your answer to the nearest tenth. Only type in the number, no units.]

Respuesta :

Answer:

3.28 cm

Step-by-step explanation:

The computation is shown below:

The Radius of a circle be R

And, An arc be A

So, the length of the arc would be

L = (A ÷ 360°) × 2 × 3.14 × R

Here R = 6 cm

Angle = 5 minutes and 15 seconds

As we know that the clock has the complete revolution in 60 minutes

So  

60 minutes = 360°

As we know that

60 seconds = 1 min

 So,

1 = 1min ÷ 60seconds  

15 seconds = 15 seconds × ((1 ÷ 60)

= (15 ÷ 60) min

= 0.25 min

So,

5 minutes and 15 seconds

= 5 min + 0.25 min

= 5.25 min

60 minutes = 360°

So,  

1 = 360° ÷ 60min

For  5.25min

= (5.25min) × (360° ÷ 60min)

= 31.5°

Then we have A = 31.5°

Now the far would be  

L = (31.5° ÷ 360°) × 2 × 3.14 × 6cm

= 3.28 cm

Otras preguntas