Answer:
The volume of a 0.2 M solution containing 8.5 grams of AgNO₃ is 0.25 L
Explanation:
Molarity (M) is a common way of expressing the concentration of solutions. It is defined as the number of moles of solute per volume of solution. The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution.
[tex]Molarity=\frac{number of moles of solute}{volume}[/tex]
Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].
Being the molar mass of AgNO3 169.87 g / mol, then you can apply the following rule of three: if 169.87 grams are present in 1 mole of the compound, 8.5 grams will be present in how many moles?
[tex]amount of moles=\frac{8.5 grams*1 mole}{169.87 grams}[/tex]
amount of moles= 0.05
So, being the molarity equal to 0.2 M, replacing in the definition of molarity:
[tex]0.2 M=\frac{0.05 moles}{volume}[/tex]
and solving you get:
[tex]volume=\frac{0.05 moles}{0.2 M}[/tex]
volume=0.25 L
The volume of a 0.2 M solution containing 8.5 grams of AgNO₃ is 0.25 L
