Answer:
The total distance the particle travels in one period is approximately 1.131 m
Explanation:
The Simple Harmonic Motion (SHM) of an object can be conceptualized as the uniform circular motion of the object projected on an axis
Therefore, the amplitude of a SHM which is the largest displacement of the motion from its central or equilibrium position is equivalent to the radius of the circular motion
Therefore;
The amplitude of the SHM, a = 0.18 m = The radius of the equivalent circular motion, r
A period of SHM = The time it takes takes to complete one revolution
Therefore, the total distance traveled in one period = The length of 1 complete revolution = The circumference of the equivalent circle describing the SHM
The circumference of the equivalent circle describing the SHM, C = 2·π·r
By substituting the known value for the radius, 'r', we have;
C = 2·π·r = 2 × π × 0.18 m ≈ 1.131 m
Therefore, the total distance the particle travels in one period ≈ 1.131 m