Answer:
v = 3.83 m/s
Explanation:
Given that,
The mass of a car, m = 0.250
It rolls down a frictionless incline from a starting height of 0.75 m
We need to find the final velocity of the car. Let v be the velocity of the car. It can be calculated using the third equation of motion i.e.
[tex]v^2-u^2=2as[/tex]
Here,
u = 0 and a = g
[tex]v=\sqrt{2gs} \\\\v=\sqrt{2\times 9.8\times 0.75} \\\\v=3.83\ m/s[/tex]
So, the final velocity of the car is 3.83 m/s.
