Answer:
20,358, 520 combinations
Step-by-step explanation:
They're interpreting the question in two different ways. If you interpret this like the number of two-handed cribbage deals** then the first player can have one of 52C6 = 20,358,520 hands, and the second player can have one of 46C6 = 9,366,819 hands, for a total of 190,694,571,947,880 possibilities.
(I think this is right, sorry if its wrong)
