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Consider the following reaction:

Cl2 + Na2S -> 2NaCl + S

The percent yield of sulfur when 71.0 g of Cl2 is reacted in excess Na2S solution is 73.0 %.
What is the actual mass of sulfur yielded by this reaction?
(Molar mass of S = 32.1 g/mol, molar mass of Cl2 = 71.0 g/mol)

__ g

Respuesta :

Answer:

23.4

Explanation:

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23.4 g mass of sulfur yielded by this reaction.

[tex]Percentage yield = (Actual / Theoretical)\times 100[/tex]

The theoretical yield for S is as follows:-

[tex]71.0\ gCl_2\times\frac{1\ molCl_2}{71\ g Cl} \times\frac{1}{1} \ mol\times\frac{32.1\ g}{molS} =32.1\ gS[/tex]

Actual yield=[tex]32.1\ gS\times73\%=23.4\ g\ S[/tex]

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