[tex]\bf{ \underline{Given:- }}[/tex]
[tex] \sf• \: We \: have \: 12 \: ohms \: of \: resistance, \: 9 \: amps \: of \: current.[/tex]
[tex] \\ [/tex]
[tex]\bf{ \underline{To \: Find :- }}[/tex]
[tex] \sf{• \: The \: Voltage\: within \: the\: circuit. }[/tex]
[tex] \\ [/tex]
[tex] \huge\bf{ \underline{ Solution:- }}[/tex]
[tex] \sf According \: to \: the \: question, [/tex]
[tex] \sf• \: Current \: (I) = 9 \: Amps.[/tex]
[tex] \sf• \: Resistance \: (R) = 12 \: Ω[/tex]
[tex] \sf{We \: know \: that, }[/tex]
[tex] \bf \red{ \bigstar{ \: V = IR }}[/tex]
[tex] \rightarrow \sf V = 9 \times 12[/tex]
[tex] \rightarrow \sf V = 108[/tex]
[tex] \\ [/tex]
[tex] \sf \purple{Therefore, \: the \: voltage \: within \: the \: circuit \: is \: 108 \: v \: .}[/tex]
