Answer:
The probability of two healthy Tay-Sachs carriers having a child that has the disease will be [tex]25[/tex] %
Explanation:
It is given that Tay Sachs is a recessive disorder which means the genotype must both recessive allele.
Let the dominant normal allele be T and the recessive diseased allele be t
Genotype of a healthy Tay-Sachs carriers will be Tt
Tt * Tt
TT, Tt, Tt, tt
Only child with genotype tt will have Tay-Sachs disease
Hence the probability of two healthy Tay-Sachs carriers having a child that has the disease will be [tex]\frac{1}{4} * 100 = 25[/tex] %
