A restaurant makes pizzas with 6-inch diameters ad 12-inch diameters. Which of the following statement is true?

The area of the 12-inch pizza is twice the area of the 6- inch pizza

The area of the 12-inch pizza is three times the area of the 6-inch pizza

the area of the 6-inch pizza is 1/4 the area of the 12-inch pizza

the area of the 6-inch pizza is 1/6 the area of the 12-inch pizza

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Answer:

The correct option is c: the area of the 6-inch pizza is 1/4 the area of the 12-inch pizza.

Step-by-step explanation:

The area (A) of each pizza is given by:

[tex] A = \pi r^{2} [/tex]

Where:

r: is the radius

For the 12-inch pizza we have:

[tex] A_{12} = \pi (\frac{12 inch}{2})^{2} = 113.1 inch [/tex]

And for the 6-inch pizza we have:

[tex] A_{6} = \pi (\frac{6 inch}{2})^{2} = 28.3 inch [/tex]

The ratio between A₆ and A₁₂ is:

[tex] \frac{A_{6}}{A_{12}} = \frac{28.3 inch}{113.1 inch} = 0.25 = \frac{1}{4} [/tex]

Hence:

[tex] A_{6} = \frac{A_{12}}{4} [/tex]

Therefore, the correct option is c: the area of the 6-inch pizza is 1/4 the area of the 12-inch pizza.

I hope it helps you!            

The area of the 6-inch pizza is 1/4 the area of the 12-inch pizza

Given that;

Diameter of pizza A = 12 inch

Diameter of pizza B = 6 inch

Computation:

Ration of Area of Pizza A to B = [πr1²] / [πr2²]

Ration of Area of Pizza A to B = [(12/2)²] / [(6/2)²]

Ration of Area of Pizza A to B = [(6)²] / [(3)²]

Ration of Area of Pizza A to B = 36 / 9

Ration of Area of Pizza A to B = 4:1

So,

Option "C" is the correct answer of the following question.

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https://brainly.com/question/21454181?referrer=searchResults