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PLS HELP 100PTS AND BRAINLIEST
What pair of numbers (x, y) will satisfy both equations below?

3x+y=10

−4x+2y=0


A.)x=3 and y = 1y=1 or (3,1)


B.)x=1 and y=2 or (2,1)


C.)x=10 and y=20 or (10,20)


D.)x=2 and y=4 or (2,4)

Respuesta :

semsee45

Answer:

D)   x = 2  and  y = 4  or  (2, 4)

Step-by-step explanation:

Given system of equations:

[tex]\begin{cases}3x+y=10\\-4x+2y=0\end{cases}[/tex]

Multiply Equation 1 by -2:

[tex]\implies -6x-2y=-20[/tex]

Add this to Equation 2 and solve for x:

[tex]\implies (-4x+(-6x))+(2y-2y)=(0+(-20))[/tex]

[tex]\implies -10x=-20[/tex]

[tex]\implies x=2[/tex]

Substitute the found value of x into Equation 1 and solve for y:

[tex]\implies 3(2)+y=10[/tex]

[tex]\implies 6+y=10[/tex]

[tex]\implies y=10-6[/tex]

[tex]\implies y=4[/tex]

Therefore, the pair on numbers (x, y) that satisfies both equations is (2, 4)

(2,4)

Let's verify

#1

  • 3(2)+4
  • 6+4
  • 10

Verified

#2

  • -4(2)+2(4)
  • -8+8
  • 0

Verified

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