Researchers wanted to see which species of lizard (A, B, or C) is most likely to survive a bacterial infection. So they infected a total of 38 lizards and recorded how many survived after 48 hours. Of the 15 species B lizards, 40% survived. For those that were species C, one more survived than died. And of the 24 lizards that died, one-third of them were species A.

a. Create a contingency table to display this data.

b. What proportion of these lizards in this study were either species A or B?

c. What is the probability that a species C lizard in this study did not survive?

Question

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batolisis batolisis · Answer 1 · 2021-02-13T10:23:59+01:00

Answer:

A) attached below

B) 0.61

C) 0.47

Step-by-step explanation:

Given data:

Total number of lizards infected = 38

Of the 15 species B lizards 40% survived

For specie C one more survived than died

Out of the 24 lizards that died 1/3 were species A

A) contingency table

attached below

B) Determine the proportion of these lizards in this study that were either specie A or Specie B

P ( A or B ) = ( 8 + 15 ) / 38 = 0.605 ≈ 0.61

C) determine the probability that specie C lizard did not study

P ( not surviving | C ) = 7 / 15 = 0.466 ≈ 0.47