Answer:
-7, -6, -5, -4, -3
Step-by-step explanation:
Given:
2x + 5 < 0
x > -8
Thus, we can combine both statements to find out integers that satisfy both inequalities.
2x + 5 < 0
Let's find x
2x < 0 - 5 (substraction property)
2x < -5
Divide both sides by 2
x < -5/2
This implies that -5/2 is greater than the set of values of x.
The second inequality, x > -8 implies that -8 is less than the value of x.
Les combine both:
-8 < x < -5/2
Therefore, the possible set of integers are whole numbers between the range of -8 and -5/2 which excludes -8 and -5/2.
Thus, they are:
-7, -6, -5, -4, -3
