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A box weighing 2000N is sliding across a cement floor. The force pushing the box is 500N, and the coefficient of sliding friction between the box and the floor is 0.20. What is the acceleration of the box? 

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tsuarez5643

Answer:

I couldn't send you this over comments so you could keep your points but this is from an article I found that breaks it down. I hope it helps. I'm sorry I've never taken physics but wanted to help you.

Explanation:

Example 1

A box weighing 2000. N is sliding across a cement floor. The force pushing the box is 500. N, and the coefficient of sliding friction between the box and the floor is 0.20. What is the acceleration of the box?

In this case, the box is sliding along the ground, so the normal force for the box is equal to its weight. Using the normal force and the coefficient of friction, we can find the frictional force. We can also find the mass of the box from its weight since we know the acceleration due to gravity. Then we can find the net force and the acceleration.

FF=μFN=(0.20)(2000. N)=400. N

mass of box=weightg=2000. N9.8 m/s2=204 kg

FNET=pushing force−frictional force=500. N−400. N=100. N

a=FNm=100. N204 kg=0.49 m/s2

hamzaahmeds

This question involves the concepts of frictional force, Newton's Second Law of Motion, and acceleration.

The acceleration of the box is "0.49 m/s²".

According to Newton's Second Law of Motion:

[tex]Net\ Force = ma\\F - f = ma[/tex]

where,

F = Pushing force = 500 N

f = frictional force = μN

μ = coefficient of friction = 0.2

N = Normal Force = Weight = 2000 N

m = mass of box = [tex]\frac{N}{g}=\frac{2000\ N}{9.81\ m/s^2}=203.9\ kg[/tex]

a = acceleration = ?

Therefore,

[tex]500\ N -\mu N=(203.9\ kg)a\\\\\frac{500\ N - (0.2)(2000\ N)}{203.69\ kg}=a\\\\[/tex]

a = 0.49 m/s²

Learn more about Newton's Second Law of Motion here:

brainly.com/question/13447525?referrer=searchResults

The attached picture shows Newton's Second Law of Motion.

Ver imagen hamzaahmeds

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