Respuesta :
Answer:
0.58 = 58% probability that the athlete is either a football player or a basketball player
Step-by-step explanation:
We solve this question treating the probabilities as Venn's sets.
I am going to say that:
Event A: Athlete is a football player.
Event B: Athlete is a basketball player.
41% of the athletes are football players:
This means that [tex]P(A) = 0.41[/tex]
52% are basketball players
This means that [tex]P(B) = 0.52[/tex]
35% of the athletes play both football and basketball.
This means that [tex]P(A \cap B) = 0.35[/tex]
What is the probability that the athlete is either a football player or a basketball player
This is [tex]P(A \cup B)[/tex], which is given by the following equation:
[tex]P(A \cup B) = P(A) + P(B) - P(A \cap B)[/tex]. So
[tex]P(A \cup B) = 0.41 + 0.52 - 0.35 = 0.58[/tex]
0.58 = 58% probability that the athlete is either a football player or a basketball player
