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Te diagonals of Quadrilateral JKLM intersect at A. If KL ≅ J M , JK≅ L M and KA ≅ M A , which additional statement shows that JKLM is a rhombus?
Group of answer choices
JA = LA

JL ⊥ K M

m
KA = KJ

Respuesta :

Answer:

JL ⊥ KM

Step-by-step explanation:

JL ⊥ KM would make the quad a rhombus because JKLM is a parallelogram since opposite sides are congruent.  If the diagonals of a parallelogram are perpendicular, then the quad must be a rhombus.

JL must be perpendicular to KM because in a parallelogram if diagonals are perpendicular then the quadrilateral JKLM is a rhombus.

Given :

  • Quadrilateral JKLM diagonals intersect at A.
  • KL ≅ J M , JK≅ L M and KA ≅ M A

The following steps can be used in order to determine the correct statement that shows that JKLM is a rhombus:

Step 1 - Remember a quadrilateral has four sides and the sum of the interior angles of a quadrilateral is 360 degrees.

Step 2 - According to the given data, KL ≅ JM, JK ≅ LM, and KA ≅ MA.

Step 3 - So, to make JKLM a rhombus, JL must be perpendicular to KM because in a parallelogram if diagonals are perpendicular then the quadrilateral JKLM is a rhombus.

Therefore, the correct option is B).

For more information, refer to the link given below:

https://brainly.com/question/14462098

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