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A pure-breeding, tall pea plant with white flowers is crossed with a pure-breeding, short plant with red flowers. The F1 plants are tall, with red flowers. When allowed to fertilize themselves, these produce the following F2: 326 tall, red; 104 tall, white; 117 short, red; and 29 short, white. You are conducting a Chi-Square analysis and what is the null hypothesis?

Respuesta :

Answer:

Null Hypothesis -

The observed frequency is approximately equal to the expected frequency of phenotype.

Explanation:

Pure Breeding Cross - TTww x ttWW

Genotype of offspring in F2 generation - TtWw

Null Hypothesis -

The observed frequency is approximately equal to the expected frequency of phenotype.

The chi square analysis is attached

The degree of freedom for this question is 3

The p value for X^2 estimated through chi square test is 0.5

Hence the null hypothesis is accepted.

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