Answer:
Step-by-step explanation:
As before any expression of the form (a^2-b^2) will always factor to (a-b)(a+b) in this case
x^8-1/81 = (x^4-1/9)(x^4+1/9) = (x^2-1/3)(x^2+1/3)(x^4+1/9) and if we completely factor it including square roots.[tex](x-\sqrt{1/3})(x+\sqrt{1/3})(x^2+1/3)(x^4+1/9)[/tex]
