[tex]\bf{ \underline{Given:- }}[/tex]
[tex] \sf• \: Resistance \: (R) \: = 38 \: Ω[/tex]
[tex]• \sf \: Potential \: difference \: (V) \: = 240 \: v[/tex]
[tex]\bf{ \underline{To \: Find:- }}[/tex]
[tex]• \sf \: The \: current \: through \: an \: electric \: heater.[/tex]
[tex]\bf{ \underline{ Solution :-}}[/tex]
[tex] \bf \red{•\: The \: formula \: of \: Current \: (I) = \frac{V}{R}}[/tex]
[tex] \sf \rightarrow I = \frac{240}{38} [/tex]
[tex] \sf \rightarrow I = 6.32[/tex]
[tex] \sf \pink{Answer :- \: The \: current \: through \: an \: electric \: heater \: is \: 6.32 \: A.}[/tex]
