Answer:
see explanation
Step-by-step explanation:
(a)
The angle around the centre O of the circle = 360°, then
∠ AOB = 360° - 260° = 100°
Δ AOB is isosceles ( the radii OA and OB are congruent )
The altitude from O bisects ∠ AOB , thus
y = 50°
Since the triangle is isosceles the 2 base angles are congruent, so
x = [tex]\frac{180-100}{2}[/tex] = [tex]\frac{80}{2}[/tex] = 40°
(b)
∠ POR = 360° - 254° = 106°
Δ POR is isosceles (the radii OP and OR are congruent ) , then
the 2 base angles are congruent , thus
a = [tex]\frac{180-106}{2}[/tex] = [tex]\frac{74}{2}[/tex] = 37°
