Answer:
C) 90 degrees
Explanation:
If we could have an imaginative illustration about what the question is all about.
We could think of the velocity of the river (V_r cosθ) as a horizontal component and the velocity of the boat (V_b sinθ) as the vertical component.
So the velocity of the boat V_b = 2.2 m/s; &
the velocity of the river V_r = 1.1 m/s
∴
The minimum time (which is the shortest time) required for the boat to cross the river is θ = 90°
the time require is:
[tex]t = \dfrac{d}{v_b \ sin \theta}[/tex]
[tex]t = \dfrac{95}{2.2}[/tex]
t = 43.18 sec