Answer:
Option C, dP/dt=1/5P
Step-by-step explanation:
The change is population of insects is directly proportional to the rate of change of population
Hence,
[tex]\frac{dP}{dt} \alpha P[/tex]
Or [tex]\frac{dP}{dt} = kP[/tex]
where K is the proportional constant
We will find the value of k
Keeping the given values of rate of change of population and population in above equation, we get -
[tex]\frac{2}{10} = k\\k = \frac{1}{5}[/tex]
Hence,
[tex]\frac{dP}{dt} = \frac{1}{5} P[/tex]