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Question 1
18 pt
A Merry-Go-Round revolves 6 times per minute, Jack is 10 feet from the center
while Bob is 14 feet from the center. (calculator allowed)
Jack's linear speed is (Select ]
feet per minute.
V
Bob's linear speed is Select !
feet per minute.

Respuesta :

Bob's linear speed is higher than Jack's because the radius of the circle

around which Bob rotates is larger.

Responses:

  • Jack's linear speed is approximately 377 feet per minute
  • Bob's linear speed is approximately 527.8 feet per minute

What is the relationship between linear speed and angular speed?

Given:

The rotational speed of the merry go round = 6 revolution per minute

Jack's distance from the center = 10 feet

Bob's distance from the center = 14 feet

The angular speed, ω, of the merry-go-round is found as follows;

  • [tex]\omega = \mathbf{\dfrac{6 \times 2 \cdot \pi}{1 \ minute}} = 12 \cdot \pi \ rad/minute[/tex]
  • Linear speed = ω × r

Which gives;

  • Jack's linear speed = 12·π rad/min × 10 feet ≈ 377 feet per minute
  • Bob's linear speed = 12·π rad/min × 14 feet ≈ 527.8 feet per minute

Learn more about angular speed and linear speed here:

https://brainly.com/question/8058144