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A motorcyclist is traveling north on a road at a speed of 23.0 m/s. A police car, traveling south at a speed of 40.0 m/s, approaches with its siren producing sound at a frequency of 2500 Hz. (Enter your answers in Hz. Assume that the speed of sound in air is 343 m/s.) (a) What frequency does the motorcyclist observe as the police car approaches

Respuesta :

Answer:

  f ’= 3019.8 Hz

Explanation:

This is an exercise of the Doppler effect, that is, of the relative movement of the source (s) and the observer (o)

         [tex]f' = f_o \frac{v +v_o}{v -v_s}[/tex]

in the case of the source and the observer approaching, if they move away the signs are exchanged

let's calculate

       f ’= 2500 [tex]\frac{343 + 23}{343 - 40}[/tex]

       f ’= 2500 [tex]\frac{366}{303}[/tex]

       f ’= 3019.8 Hz

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