Answer:
[tex]3x+10\leq 30\\Subtracting~10~on`both~sides,\\3x+10-10\leq 30-10\\or, 3x\leq 20\\Dividing ~by~3~on~both~sides,\\\frac{3x}{3}\leq \frac{20}{3}\\or, x\leq \frac{20}{3}[/tex]
