Evaluate 8p +3q-188p+3q−188, p, plus, 3, q, minus, 18 when p=\dfrac12p= 2 1 ​ p, equals, start fraction, 1, divided by, 2, end fraction and q=7q=7q, equals, 7.

Respuesta :

Given:

The expression is

[tex]8p+3q-18[/tex]

To find:

The value of the expression when [tex]p=\dfrac{1}{2}[/tex] and [tex]q=7[/tex].

Solution:

We have,

[tex]8p+3q-18[/tex]

Putting [tex]p=\dfrac{1}{2}[/tex] and [tex]q=7[/tex], we get

[tex]8(\dfrac{1}{2})+3(7)-18[/tex]

[tex]=4+21-18[/tex]

[tex]=7[/tex]

Therefore, the value of the expression is 7 when [tex]p=\dfrac{1}{2}[/tex] and [tex]q=7[/tex].

Answer: 7

Step-by-step explanation: