Answer:[tex]\frac{17}{35}[/tex]
Step-by-step explanation:
Given
The bag contains 6 orange and 9 lime sweets
For both sweets of the same flavor, Jodi must either choose orange or lime
No. of ways it can be done is [tex]^6C_1\times^5C_1+^9C_1\times^8C_1[/tex]
The total no of ways of selecting two sweets out of 15 is [tex]^{15}C_1\times^{14}C_1[/tex]
The probability that both sweets are the same flavor
[tex]P=\dfrac{^6C_1\times^5C_1+^9C_1\times^8C_1}{^{15}C_1\times^{14}C_1}=\frac{102}{210}=\frac{51}{105}=\frac{17}{35}[/tex]
