In this exercise we have to use the knowledge of speed to calculate the speed each family achieves, thus we find that:
- Family 1 the average rate of speed for each family is 66 miles per hour.
- Family 2 the average rate of speed for each family is 54 miles per hour
Since two families that live 270 mi apart plan to meet at a park located between their two homes, and both leave at 9:00 am but one family averages 12 mph faster than the other family, if the families meet at the designated spot 2 and half hours later, to determine the average rate of speed for each family, the following calculation must be performed:
So looking at family 1 we found that:
[tex]F_1:\frac{ ((\frac{270}{2.5})+(12*2.5))}{2.5} \\F_1: \frac{(135 + 30)}{2.5}\\F_1: \frac{165}{2.5}\\F_1: 66 \ miles \ per \ hour[/tex]
So looking at family 2 we found that:
[tex]F_2: \frac{(\frac{270}{2})}{2.5}\\F_2: \frac{135}{2.5}\\F_2: 54 \ miles \ per \ hour[/tex]
See more about speed at brainly.com/question/7359669
