Answer:
C = 1.01
Explanation:
Given that,
Mass, m = 75 kg
The terminal velocity of the mass, [tex]v_t=60\ m/s[/tex]
Area of cross section, [tex]A=0.33\ m^2[/tex]
We need to find the drag coefficient. At terminal velocity, the weight is balanced by the drag on the object. So,
Weight of the object = drag force
R = W
or
[tex]\dfrac{1}{2}\rho CAv_t^2=mg[/tex]
Where
[tex]\rho[/tex] is the density of air = 1.225 kg/m³
C is drag coefficient
So,
[tex]C=\dfrac{2mg}{\rho Av_t^2}\\\\C=\dfrac{2\times 75\times 9.8}{1.225\times 0.33\times (60)^2}\\\\C=1.01[/tex]
So, the drag coefficient is 1.01.
