There are 4 white marbles, 6 red marbles, and 2
blue marbles. Once a marble is selected, it is not
replaced. Find the probability of selecting 2 blue
marbles.

Respuesta :

Answer:

For first question, there is 12 marbles at first. So the probability of choosing blue marble is 3/12=1/4. Then marbles are not replaced, the total number is 11. The probability of choosing red is 5/11. So the finally answer is (1/4)*(5/11)=5/44. The same method for second question. Need to notice that you have already choose 1 white marble, so the number of white marble also changed. The answer is (4/12)*(3/11)=1/11.

Step-by-step explanation:

The probability of selecting 2 blue marbles without replacement will be 1/66.

What is probability?

Its simple notion is that something will most likely occur. The favorable event's proportion to the overall number of occurrences.

There are 4 white marbles, 6 red marbles, and 2 blue marbles.

Once a marble is selected, it is not replaced.

Then the total number of the marbles will be

Total marbles = 4 + 6 + 2

Total marbles = 12

Then the probability of selecting 2 blue marbles without replacement will be

P = 2/12 x 1/11

P = 2/132

P = 1/66

More about the probability link is given below.

https://brainly.com/question/795909

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