Answer:
[tex]10\:\mathrm{meters}[/tex]
Step-by-step explanation:
We can use trigonometry for a right triangle to solve this problem:
[tex]\tan 18^{\circ}=\frac{h}{30},\\h=30\cdot\tan 18^{\circ},\\h\approx \fbox{$10\:\mathrm{m}$}[/tex].
The height of the flagpole is 10 meters.
"It is the angle from the horizontal upward to an object."
For given question,
Consider the following figure.
The angle of elevation is 18°
⇒ ∠ACB = 18°
Also, BC = 30 meters
We need to find the height of the flagpole i.e., we need to find the distance AB.
Consider a tan(∠ACB )
[tex]\Rightarrow tan(18^{\circ})=\frac{AB}{BC}\\\\ \Rightarrow 0.3249 = \frac{AB}{30}\\\\ \Rightarrow AB=9.747 ~~meters\\\\\Rightarrow AB\approx 10~~meters[/tex]
Therefore, the height of the flagpole is 10 meters.
Learn more about angle of elevation here:
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