Find x and y so the quadrilateral is a parallelogram.
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Answer:
We conclude that:
Step-by-step explanation:
Given
We know that the diagonals of a parallelogram bisect each other.
so
[tex]RT = TP[/tex]
Given
so substituting RT = x, and TP = 5x-28
[tex]RT = TP[/tex]
[tex]x = 5x-28[/tex]
[tex]5x = x+28[/tex]
[tex]5x-x = 28[/tex]
[tex]4x = 28[/tex]
divide both sides by 4
[tex]4x/4 = 28/4[/tex]
[tex]x = 7[/tex]
Therefore, the value of x:
Similarly,
[tex]QT = TS[/tex]
Given
so substituting QT = 5y, and TS = 2y+12
[tex]QT = TS[/tex]
[tex]5y = 2y+12[/tex]
[tex]5y-2y = 12[/tex]
[tex]3y = 12[/tex]
divide both sides by 3
[tex]3y/3 = 12/3[/tex]
[tex]y = 4[/tex]
Therefore, the value of y:
y = 4
Therefore, we conclude that: