Answer:
We can conclude that the distance from Sandy's Hotel to Trader Joes' Store is:
Step-by-step explanation:
From the coordinate plane, we can clearly identify that:
- Sandy's Hotel is located at the point (-8, 9)
- Trader Joes' Store is located at the point (-4, 2)
The distance from Sandy's Hotel to Trader Joes' Store can be calculated such as:
[tex]d=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}[/tex]
The distance between (-8, 9) and (-4, 2)
[tex]d=\sqrt{\left(-4-\left(-8\right)\right)^2+\left(2-9\right)^2}[/tex]
[tex]=\sqrt{\left(-4+8\right)^2+\left(2-9\right)^2}[/tex]
[tex]=\sqrt{4^2+7^2}[/tex]
[tex]=\sqrt{16+49}[/tex]
[tex]=\sqrt{65}[/tex]
[tex]=8.06[/tex] miles
Therefore, we can conclude that the distance from Sandy's Hotel to Trader Joes' Store is:
