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Assume that Q, R, and S are the angles of a triangle, with opposite sides q, r, and s respectively. Select all of the following that represent the law of cosines. q2 = r2 + s2 – 2rscos(Q) . q2 = r2 + s2 – 2qscos(R) . r2 = q2 + s2 – 2qscos(Q) . r2 = q2 + s2 – 2qscos(R) .s2 = q2 + r2 – 2qrcos(S)

Respuesta :

Answer:

A. q2 = r2 + s2 – 2rscos(Q)

D. r2 = q2 + s2 – 2qscos(R)

E. s2 = q2 + r2 – 2qrcos(S)

Step-by-step explanation:

The following relation represent the law of cosines.

                  [tex]q^{2}=r^{2}+s^{2} -2rscos(Q) \\\\r^{2}=q^{2}+s^{2} -2qscos(R) \\\\s^{2}=r^{2}+q^{2} -2rqcos(S)[/tex]

Law of cosines:

The law of cosine states that the square of any one side of a triangle is equal to the difference between the sum of squares of the other two sides and double the product of other sides and cosine angle included between them.

It is given that, Q, R, and S are the angles of a triangle, with opposite sides q, r, and s respectively.

A diagram is attached below,

From cosines law,

      [tex]q^{2}=r^{2}+s^{2} -2rscos(Q) \\\\r^{2}=q^{2}+s^{2} -2qscos(R) \\\\s^{2}=r^{2}+q^{2} -2rqcos(S)[/tex]

Above relation represent law of cosines.

Learn more about the Law of cosines here:

https://brainly.com/question/4372174

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