Find x and y so the quadrilateral is a parallelogram
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Answer:
Result
Step-by-step explanation:
Given the parallelogram
Here are some of the properties of a parallelogram:
We know that the diagonals of a parallelogram bisect each other.
In our case, the diagonals PR and QS bisect each other.
Thus, we get
Given RT = x and TP = 5x-28, so
[tex]x = 5x-28[/tex]
[tex]5x-x = 28[/tex]
[tex]4x = 28[/tex]
divide boh sides by 4
[tex]4x/4 = 28/4[/tex]
[tex]x = 7[/tex]
Similarly, we can determine the value of y.
As
[tex]QT = TS[/tex]
Given QT = 5y and TS = 2y+12, so
[tex]5y = 2y+12[/tex]
[tex]5y-2y = 12[/tex]
[tex]3y = 12[/tex]
divide both sides by 3
[tex]3y/3 = 12/3[/tex]
[tex]y = 4[/tex]
Result