sofiesnapple1234 sofiesnapple1234
  • 16-01-2021
  • Mathematics
contestada

Given f (x) = 1/5 (6 – x)^2 what is the value of f(16)?​

Respuesta :

wrobinson4854 wrobinson4854
  • 16-01-2021
f(16)=1/5(6-16)^2
f(16)=1/5(-10)^2
f(16)=1/5(100)
f(16)=20
Answer Link
nahume94
nahume94 nahume94
  • 16-01-2021

Answer:

20

Step-by-step explanation:

if f(x)=1/5(6-x)^2 when f(16)you will replace x by 16 then solve it like this

f(16)=1/5(6-16)^2

= 1/5(-10)^2

=1/5(100)

=20

Answer Link

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