Answer:
Yes, it would be enough.
Explanation:
The volume of the tank (cylinder tank) is given by the following equation:
[tex]V_{initial}=\pi (\frac{D}{2})^{2}h[/tex]
Where:
D is the diameter of the tank
h is the height of the tank
Now, the engineer makes a tank 1.26 times as big in heigh and 1.41 times as large with respect to diameter, then the new volume of this tank will be:
[tex]V_{new}=\pi (\frac{1.41D}{2})^{2}1.26h[/tex]
[tex]V_{new}=1.41^2*1.26\pi (\frac{D}{2})^{2}h[/tex]
[tex]V_{new}=2.51\pi (\frac{D}{2})^{2}h[/tex]
in terms of the initial volume:
[tex]V_{new}=2.51V_{initial}[/tex]
Which means that the volume of the water could be doubled.
I hope it helps you!
