Answer:
The speed of the wave as it travelled through the brass bell is;
B. 4,700 m/s
Explanation:
The given parameters are;
The wavelength of the sound wave produced from the brass bell, [tex]\lambda _{(air)}[/tex] = 3.5 m
The wavelength of the wave in the brass bell, [tex]\lambda _{(brass \ bell)}[/tex] = 47 m
The frequency of the wave in the brass bell, f = 100 Hz
The given equation for wave speed, v = f × λ
Therefore, the speed of the wave as it travelled through the brass bell, [tex]v _{(brass \ bell)}[/tex], is given as follows;
[tex]v _{(brass \ bell)}[/tex] = f × [tex]\lambda _{(brass \ bell)}[/tex] = 100 Hz × 47 m = 4,700 m/s
The speed of the wave as it travelled through the brass bell = [tex]v _{(brass \ bell)}[/tex] = 4,700 m/s
