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A Petri dish is growing bacteria. It starts with 3 cells on day 1, 9 cells on day 2, and continues tripling the number of cells every day after that. How many cells of bacteria are there on day 5? 3 5 5 3 15 18

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Answer:

243

Step-by-step explanation:

Given that:

Day 1 = 3

Day 2 = 9

After the 2nd day, number of cells continue to triple ;

Day 3 = 9^3

P(t) = 9 * 3^3

P(t) = 9 * 27

= 243

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