Step-by-step explanation:
[tex] \underline{ \underline{ \text{Given}}} : [/tex]
- Length of MN ( Base ) = 8
- Length of NL ( Hypotenuse ) = 10
[tex] \underline{ \underline{ \text{To \: find}}} : [/tex]
- Length of LM ( Perpendicular )
[tex] \underline{ \underline{ \text{Using \: pythagoras \: theorem}}} : [/tex]
[tex] \boxed{ \sf{ {Hypotenuse}^{2} = {Perpendicular}^{2} + {Base}^{2} }}[/tex]
⤑ [tex] \sf{ Perpendicular = \sqrt{ {(Hypotenuse)}^{2} - {(Base)}^{2} } }[/tex]
⤑ [tex] \sf{ \sqrt{ {(10)}^{2} - {(8)}^{2} } }[/tex]
⤑ [tex] \sf{ \sqrt{100 - 64}} [/tex]
⤑ [tex] \sf{ \sqrt{36}} [/tex]
⤑ [tex] \boxed{ \sf{6\: units}}[/tex]
[tex] \pink{ \boxed{ \boxed{ \tt{Our \: final \: answer : \boxed{ \underline { \tt{6 \: units}}}}}}}[/tex]
Hope I helped ! ツ
Have a wonderful day / night ! ♡
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