Answer:
Given: Water in a reservoir dropped by 60%
Step-by-step explanation:
let the total water level of reservoir be 100.
then, in first year
the water reservoir dropped = 60% of 100
=[tex]\frac{60}{100}[/tex] * 100
= 60
therefore, total water level needed to be restored till next year= 100
remaining water level to restore till next year= 100-60
=40
percentage= [tex]\frac{40}{100}[/tex] * 100
=40%
