Respuesta :
Answer:
The answer is "[tex]\bold{\frac{2 \pi}{3}}[/tex]"
Step-by-step explanation:
Please find the complete question in the attached file.
Using formula:
[tex]\to \bold{\theta = \frac{S}{r}}[/tex]
Where,
[tex]\theta =central \ angle \\\\{S} = arc \ length\\\\{r} = radius \ length[/tex]
[tex]\to \theta = \frac{PQ }{OQ}[/tex]
[tex]=\frac{6 \pi}{9} \\\\ = \frac{2 \pi}{3}[/tex]
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The radian measure of central angle POQ is 3π/4 radians. Option b) is the correct option.
Line segments PO and QO are radii.
We need to find the radian measure of central angle POQ.
How to find the relation between angle subtended by the arc, the radius and the arc length?
[tex]2\pi^c = 360^\circ = \text{Full circumference}[/tex]
The superscript 'c' shows angle measured is in radians.
If the radius of the circle is of r units, then:
[tex]1^c \: \rm covers \: \dfrac{circumference}{2\pi} = \dfrac{2\pi r}{2\pi} = r\\\\or\\\\\theta^c \: covers \:\:\: r \times \theta \: \rm \text{units of arc}[/tex]
We know that
π radians = 180°
Therefore,
180° = π radians
135° = x
180° × x = 135° × π radians
x = 135° × π radians/180
x = 3π/4 radians
Hence, the radian measure of central angle POQ is 3π/4 radians. Option b) is the correct option.
Learn more about angle, arc length relation here:
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